erichenkell2280
29.07.2019 •
Chemistry
What is the molality of a solution that contains 75.2 grams of agclo4 in 885 grams of benzene? question 5 options: 0.41 m 4.10 m 8.20 m 0.83 m
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Ответ:
molality = moles solute / kg solvent
moles AgClO4 = 75.2 g / 207.389 g/mol
= 0.3626 mol
molality = 0.6326 mol / 0.885 kg
= 0.410 m
The asnwer is 0.41.
Ответ:
Diamond
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