What is the molarity of a 0.5 L solution containing 20.0 grams of sucrose (molar mass of sucrose 342.3 g/mol)?​

Molarity of sucrose = 0.116 M (Approx.)

Explanation:

Given:

Volume of solution = 0.5 liter

Mass of sucrose in gram = 20 gram

Molar mass of sucrose 342.3 g/mol

Find:

Molarity of sucrose

Computation:

Mole of sucrose = Mass of sucrose in gram / Molar mass of sucrose

Mole of sucrose = 20 / 342.3

Mole of sucrose = 0.058 (Approx.)

Molarity of sucrose = Mole of sucrose / Volume of solution

Molarity of sucrose = 0.058 / 0.5

Molarity of sucrose = 0.116 M (Approx.)