What is the net ionic equation of the reaction of zncl2 with naoh?
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Ответ:
ZnCl₂ + 2NaOH → Zn(OH)₂↓ + 2NaCl
Explanation:
ZnCl₂ reacts with NaOH to produce a white precipitate of Zn(OH)₂ and NaCl.The net ionic equation of the reaction is:ZnCl₂ + 2NaOH → Zn(OH)₂↓ + 2NaCl
Ответ:
b) the limiting reactant is f2 (fluorine). we obtain 2*3.68/3=2.453 moles of chlorine trifluoride.