What is the percent by mass of carbon in acetone c3h6o

Well, the molar mass of acetone would be

3(12.011)+6(1.008)+15.999 , which cleans up to be 58.08 grams.

out of this total, 3(12.011), or 36.033 grams are carbon

So, to find the percent, you do part over whole

36.033/58.08, which equals 0.6204 with significant figures

multiply that by 100 to get 62.04%

Hope that helps!

62.07% is the percent by mass of carbon in acetone.

Explanation:

Percentage of an element in a compound:

Molar mass of acetone =58 g/mol

Number of carbon atom in acetone = 3

Atomic mass of carbon = 12 g/mol

Percentage of carbon in acetone:

550 J

Explanation:

The formula for the amount of heat (q) released by the copper is

q = mCΔT

Data:

  n = 0.762 mol

  C = 0.386 J°C⁻¹g⁻¹

T_i = 81.6 °C

T_f = 52.2 °C  

Calculations:

(a) Mass of copper

\text{Mass} = \text{0.762 mol} \times \dfrac{\text{63.55 g}}{\text{1 mol}} = \text{48.43 g}

(b) ΔT

ΔT = 81.6 °C - 52.2 °C = 29.4 °C

(c) q

q = mCΔT = 48.43 g × 0.386 J·°C⁻¹g⁻¹ × 29.4 °C = 550 J

The amount of heat released by the copper is 550 J.