What is the pH of a solution of a 3.4 x 10-8 M [H"] solution if its pOH = 7.5?

pH =​

6.5

Explanation:

14-7.5 = 6.5

HCl(aq) + KOH(aq) —> KCl(aq) + H2O(l)

Explanation:

Aqueous solution of HCl and aqueous solution of KOH react as follow:

HCl(aq) + KOH(aq) —>

In solution, HCl and KOH will dissociates as follow:

HCl —> H+ + Cl-

KOH —> K+ + OH-

During the reaction, a double displacement reaction occur as shown below:

H+ + Cl- + K+ + OH- —> K+Cl- + H+OH-

The elemental equation is given below:

HCl(aq) + KOH(aq) —> KCl(aq) + H2O(l)