What is the rate constant at 25.0 ∘c based on the data collected for trial b? the following data were acquired in an iodination experiment involving acetone. all reaction times are in terms of the rate of disappearance of i2. trial 1st #-volume of 0.0010 m i2 (ml) 2nd #- volume of 0.050 m hcl(ml) 3rd #- volume of 1.0 m acetone(ml) 4th #- volume of water(ml) 5th #-temperature(∘c) 6th#-reaction time(s) a 5.0 10.0 10.0 25.0 25.0 130 b 10.0 10.0 10.0 20.0 25.0 249 c 10.0 20.0 10.0 10.0 25.0 128 d 10.0 10.0 20.0 10.0 25.0 131 e 10.0 10.0 10.0 20.0 42.4 38
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Ответ:
carbon number 3 of the parent chain
Explanation:
CH3CH2CH(CH3)C(CH3)2CH3.
Looking at the structural formula of the above compound, the carbon on position 3, in the parent chain is a tertiary carbon atom. The reaction in question proceeds by free radical mechanism. Hydrogen is first abstracted from the carbon atom that leads to te formation of the most stable carbocation. For this reason, hydrogen is abstracted from carbon 3 of the parent chain.