Chemistry: What is the specific heat of a 85.01 g piece of an unknown metal that exhibits a 45.2°C temperature change upon absorbing 1870 J of heat?

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What is the specific heat of a 85.01 g piece of - id85017036873, Hellopeople233

july00

29.01.2022

$0.48~\frac{J}{g~^{\circ}C}$

Explanation:

In this question, we have to remember the relationship between Q (heat) and the specific heat (Cp) the change in temperature (ΔT), and the mass (m).

Q=m*Cp*ΔT

The next step is to identify what values we have:

Q~=~1870~J

m~=~85.01~g

$ΔT~=~45.2~^{\circ}C$

Cp~=~X

Now, we can plug the values and solve for "Cp":

$1870~J=~85.01~g~*Cp*45.2~^{\circ}C$

$Cp=\frac{1870~J}{85.01~g~*45.2~^{\circ}C}$

$Cp=0.48~\frac{J}{g~^{\circ}C}$

The unknow metal it has a specific value of $0.48~\frac{J}{g~^{\circ}C}$

I hope it helps!

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