What is the specific heat of a piece of tin if it measures 36.0g and is heated from 18.0 degrees Celsius. It must absorb 678 j of heat to reach this temperature?
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Ответ:
The answer to your question is C = 1.046 J/g°C
Explanation:
Data
Specific heat = ?
mass = 36 g
ΔT = 18°C
Q = 678 J
To calculate the specific heat, use the formula of heat and solve it for C
Formula
Q = mCΔT
Solve for C
C = Q / mΔT
Substitution
C = 678 / (36 x 18)
Simplification
C = 678 / 648
Result
C = 1.046 J/g°C
Ответ:
Negativly
Explanation: