What is the vapor pressure of the pure solvent if the vapor pressure of a solution of 10 g of sucrose (c6h12o6) in 100 g of ethanol (c2h6o) is 55 mmhg?

Explanation:

The given data is as follows.

Vapor pressure of the solution = 55 mm Hg

Mass of sucrose = 10 g

Molar mass of sucrose = 180 g/mol

Therefore, moles of sucrose present into the solution will be calculated as follows.

             No. of moles =

                                   =

                                   = 0.055 mol

Mass of ethanol is given as 100 g and its molar mass is 46 g/mol.

Hence, number of moles of ethanol will be calculated as follows.

            No. of moles =

                                  =

                                  = 2.174 mol

As mole fraction =

Hence, mole fraction of etahnol will be calculated as follows.

            =

                                              =

                                              = 0.975

Now, using Raoult's Law  as follows.

              =

                                    =

                                    = 56.4 mm Hg

Thus, we can conclude that the vapor pressure of the pure solvent is 56.4 mm Hg.

Both use ion channels to move ions across the cell membrane, in or out of the cell. Differences: Passive Transport (or Diffusion) moves ions from high concentration to low, using no metabolic energy. Active Transport moves ions from low concentration to high, using metabolic energy in the form of ATP.

Explanation: