What is the volume of 0.80 grams of o2 gas at stp?
0.59 liters
0.56 liters
0.50 liters
0.47 liters

0.56 liters

Explanation:

At STP, one mole of a gaseous substance occupy 22.4 liters.

Hence 1 mole of oxygen gas will occupy 22.4 liters at STP.

We know that molar mass of oxygen is 32 g/mol.

So 32 grams of oxygen gas will occupy 22.4 liters at STP.

Then 0.8 grams of oxygen gas will occupy:

liters.

Hence the volume of 0.8 grams of oxygen gas at STP is 0.56 liters.

Al

Explanation:

You divide the moles by the coefficient to find which one is the limiting reactant. Whichever result is lower, that's the limiting reactant.

Observe:

There were 2 moles of Al in the reaction and the coefficient behind Al is 2 - 2/2 = 1

There were 6 moles of H2O in the reaction and the coefficient behind H2O is 3 - 6/3 = 2

Since the result for Al is lower, that's the limiting reactant.