What is the volume of a marble in cubic cm with dimensions of 1.0 cm

T= 6.28fR²/µg

Explanation:

a=µg/R

(v-vi)/(t-ti)= µg/R

v: linear velocity of turntable at which coin begins to slip

vi: initial velocity

t: time at which coin begins to slide

ti: time at which turntable started moving

(v-0)/T=µg/R

T=Rv/µg

to find v,

v= wR

here, w is angular velocity and is equal to 2πf where f is frequency of turntable rotation

v= 2πfR

so,

T= R (6.28fR)/µg

T= 6.28fR²/µg