What is the work when a gas expands from 0.666 L to 2.334 L against an external pressure of 2.07 atm?
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Ответ:
work = 3.45 Joules
Explanation:
Work from the 1st Law of Thermodynamics is PΔV in the equation of internal energy => ΔE = ΔH + PΔV.
Therefore, work = PΔV = 2.07atm·(2.334L - 0.666L) = 3.45 L·atm = 3.45 Joules
Ответ: