What kind of bond is formed when lithium and fluorine combine to form lithium fluoride?

The answer to your question is Ionic bonding.

Explanation:

There are three main types of bonding:

- Ionic bonding is when a metal attaches to a nonmetal and the electronegativity is higher than 1.7.

- Covalent bonding is when a non metal attaches to another non metal. and the electronegativity is between 0 and 1.7.

- Metallic bonding is a bond between metals.

In this question, we have      Lithium plus fluorine

Formula                                               LiF    

In this compound there a metal and a nonmetal

Electronegativity    Fluorine = 3.98     Lithium = 0.98

Difference of electronegativity =  3.98 - 0.98 = 3.0

                                             3.0 > 1.7

Then we conclude that the bond is Ionic.                                                

Explanation:

First, a quick revision of radioactive decay:

During alpha decay, an alpha particle is emitted from the nucleus —- it is the equivalent of a helium atom (i.e. it has a mass of 4 and an atomic number of 2). So, let's take the following question:

Polonium-210 is a radioisotope that decays by alpha-emission. Write a balanced nuclear equation for the alpha decay of polonium-210.

In symbols, the equation becomes

210/84Po--->?+4/2HE

The sums of the superscripts and of the subscripts must be the same on each side of the equation.

Take 4 away from the mass number (210-4 = 206)

Take 2 away from the atomic number (84-2 = 82). Lead is element number 82.

So, the equation is

210/84 Po--->206/82Pb+4/2He

Now let's try one for beta decay — remember that, in beta decay, a neutron turns into a proton and emits an electron from the nucleus (we call this a beta particle)

Write a balanced nuclear equation for the beta decay of cerium-144)

In nuclear equations, we write an electron as 0^-1e.

144/58Ce-->144/59Pr+^0-1e

Here's a fission reaction.

A nucleus of uranium-235 absorbs a neutron and splits in a chain reaction to form lanthanum-145, another product, and three neutrons. What is the other product?

We write a neutron as 1/0n, so the equation is

235/92U +1/0n--->145/57La+X+3 1/0n

Sum of superscripts on left = 236. Sum of superscripts on right = 148. So  X

must have mass number = 236 – 148 = 88.

Sum of subscripts on left = 92. Sum of subscripts on right = 57. So  X

must have atomic number = 92 – 57 = 35. Element 35 is bromine.

The nuclear equation is

235/92U+1/0n--->145/57La+88/35Br+31/0N