What mass of Gallium chloride would react with excess fluorine to produce 78.9 g of chlorine? Gallium fluoride is the other product. 2 GaCl3 + 3 F2 2 GaF3 + 3 Cl2
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Ответ:
130.2 g
Explanation:
To calculate the moles :
According to stoichiometry :
3 moles of
require = 2 moles of ![GaCl_3](/tpl/images/0663/8024/6d516.png)
Thus 1.11 moles of
will require=
of ![GaCl_3](/tpl/images/0663/8024/6d516.png)
Mass of![GaCl_3=moles\times {\text {Molar mass}}=0.74moles\times 176g/mol=130.2g](/tpl/images/0663/8024/234c2.png)
Thus 130.2 g of gallium chloride would react with excess fluorine to produce 78.9 g of chlorine
Ответ:
1. There should be a sufficient amount of the selected isotope in the rock.
2. There should be more than one unstable isotope in the rock.
Explanation:
Use the proses of elimination!