Nibiskadhungana
22.10.2020 •
Chemistry
What mass of silver chromate (in grams) will be produced when 100.0 mL of 2.30 M silver nitrate is mixed with 300.0 mL of 1.60 M sodium chromate?
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Ответ:
38.15 g of silver chromate
Explanation:
The equation of the reaction is;
2AgNO3(aq)+Na2CrO4(aq)→Ag2CrO4(s)↓+2NaNO3(aq)
number of moles of silver nitrate = 100/1000 * 2.3 = 0.23 moles
number of moles of sodium chromate = 300/1000 * 1.6 = 0.48 moles
We shall now obtain the limiting reactant:
From the reaction equation,
2 moles of silver nitrate yields 1 mole of silver chromate
0.23 moles of silver nitrate will yield 0.23 * 1/2 = 0.115 moles of silver chromate
for sodium chromate:
1 mole of sodium chromate yields 1 mole of silver chromate
0.48 moles of sodium chromate yields 0.48 moles of silver chromate
Hence silver nitrate is the limiting reactant (it produced a lower number of moles of silver chromate-the product).
Hence, mass of silver chromate = 331.73 g/mol * 0.115 moles = 38.15 g of silver chromate
Ответ:
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Explanation:
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