MidnightAIY179
07.09.2019 •
Chemistry
What mass of solute is contained in 256ml of a 0.875 m ammonium chloride solution?
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Ответ:
Number of moles = 0.256*0.895 as M = moles/liter so 0.229 moles.
And NH4Cl has mol. wt. of 14+4*1+35.5 = 53.5 g/mole.
So 53.5*0.229 g = 12.3 g
Ответ:
m = 11.97 g
Explanation:
First, the ammonium chloride has the formula NH₄Cl. This molecule, has the elements N (MW = 14 g/mol), H (MW = 1 g/mol) and Cl (MW = 35.45 g/mol).
To get the mass of solute, we need to use the following the expression:
m = n * MM
So, in order to get the mass, we need to moles of the solute. This can be obtained with the molarity of the solution:
M = n/V > solving for n:
n = M*V
We have the volume (Which is in mL, so, we need to pass it to Liters dividing by 1000) and the molarity so, the moles of the solution are:
n = 0.875 * (256/1000)
n = 0.224 moles
We have the moles, now we calculate the molar mass of the solute:
MM = 14 + (4*1) + 35.45
MM = 53.45 g/mol
Finally the mass of the solute:
m = 0.224 * 53.45
m = 11.97 g of ammonium chlorideОтвет:
Explanation:
The key difference between electropositive and electronegative radicals is that electropositive radicals are radical compounds having the capacity to electrons and carry a positive charge whereas electronegative radicals are radical compounds having the capacity to gain electrons and carry a negative charge.
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