What volume will 2 moles of nitrogen occupy at 780 torr and 10C.

The volume : V = 45.22 L

Given

Moles = n = 2

Pressure = P = 780 torr = 1,02632 atm

Temperature = T = 10 + 273 = 283 K

Required

Volume

Solution

Ideal gas law : PV = nRT

where  

P = pressure, atm  

V = volume, liter  

n = number of moles  

R = gas constant = 0.08206 L.atm / mol K  

T = temperature, Kelvin  

Input the value :

V = (nRT)/P

V = (2 x 0.082 x 283)/1,02632

V = 45.22 L

DD

Explanation:

DD