Chemistry: What volume will be occupied by 11.7 g of Helium in a balloon at an altitude of 10.0 km if the air pressure is 0.262 atm and the temperature is -50.0 °C?

What volume will be occupied by 11.7 g of Helium

Ответ:

cearadenney7067

28.01.2022

Chemistry

204 L

Explanation:

According to ideal gas equation:

PV=nRT

P = pressure of gas = 0.262 atm

V = Volume of gas = ?

n = number of moles = $\frac{\text {given mass}}{\text {molar mass}}=\frac{11.7g}{4g/mol}=2.92$

R = gas constant = 0.0821Latm/Kmol

T =temperature = -50^0C=(273+(-50))K=223K

$V=\frac{nRT}{P}$

$V=\frac{2.92\times 0.0820 L atm/K mol\times 223K}{0.262atm}=204L$

Thus volume occupied by 11.7 g of Helium in a balloon is 204L

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Ответ:

rleiphart1

08.10.2022

Chemistry

mass changes only occur because a gas is being released into the atmosphere, or because a gas from the atmosphere is being used as a reactant - no atoms are being created or destroyed, just rearranged.

Explanation:

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What volume will be occupied by 11.7 g of Helium in a balloon at an altitude of 10.0 km if the air pressure is 0.262 atm and the temperature is -50.0 °C?

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