Chemistry: When 0.14 g of cholesterol is dissolved in 1.00 ml of ether and placed in a sample cell 10.0 cm in length, the observed rotation at 20°c (using the d line of sodium) is -0.441°. calculate the specific rotation of cholesterol.

5 peaks, as Cl2+ would share an ion with P, still in the 3p section....

When 0.14 g of cholesterol is dissolved in 1.00 ml - id0141003470951, ashleyrichard29

Wolfman2004

08.01.2022

Specific rotation of cholesterol is -3.15°.

Explanation:

Given that

Path length = 10 cm = 1 dm.

Observed rotation ,α= - 0.441 °

m= 0.14 g

V= 1 ml

The concentration of cholesterol ,c= m/V g/ml

c = 0.14 / 1 = 0.14 g/ml

We know that specific rotation given as

$[\alpha]_D=\dfrac{\alpha}{l.c}$

Now by putting the all values

$[\alpha]_D=\dfrac{\alpha}{l.c}$

$[\alpha]_D=\dfrac{-0.441}{1\times 0.14}$

$[\alpha]_D=-3.15$ °

Specific rotation of cholesterol is -3.15°.

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