When 0.440 mol of aluminum are allowed to react with an excess of chlorine gas, cl2, how many moles of aluminum chloride are produced? when 0.440 mol of aluminum are allowed to react with an excess of chlorine gas, cl2, how many moles of aluminum chloride are produced? 0.880 mol 0.440 mol 0.330 mol 0.220 mol 0.110 mol?

The  moles of aluminum  produced  when 0.440 moles  reacted  is  calculated  as below

write  the balanced equation  for reaction

2Al+3Cl2  = 2Al2Cl3

by  use  of  mole ratio  between Al to Al2Cl3  which  is  2:2  the  moles of Al2Cl3 

=  0.440 x2/2 = 0.440 moles  of AI2CI3

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