When 11.12 g of neon is combined in a 100 l container at 80oc with 9.59 g of argon, what is the mole fraction of argon?

The correct answer for the question that is being presented above is this one: "0.3."

Here it is how to solve.
Molecular mass of Ar = 40
Molecular mass of Ne = 20
Number of moles of Ar = 9.59/40 = 0.239
Number of moles of Ne = 11.12/20= 0.556
Mole fraction of argon = 0.239/ ( 0.239 + 0.556) = 0.3

The new pressure is 8.58 atm

Explanation:

Using Boyle's law which states that the pressure of a gas is inversely proportional to the volume of the gas and mathematically written as;

         P1 V1 = P2 V2

P1 = 3.7atm

V1 = 5.8L

V2 = 2.5L

P2 = ?

Equate the values to the equation and solve for P2:

P2 = P1 V1 / V2

P2 = 3.7 * 5.8 / 2.5

P2 = 21.46 / 2.5

P2 = 8.584 atm

The new pressure acting on the balloon is therefore 8.58atm