![pmbeachy3102](/avatars/25501.jpg)
pmbeachy3102
12.02.2020 •
Chemistry
When 16.0 g of an unknown compound (a nonelectrolyte) are dis solved in exactly 800. g of water, the solution has a freezing point of – 0.14 ° C. What is the molar mass of the compound? K f of water is 1.86 ° C m – 1 . A. 266 g B. 343 g C. 178 g D. 99.2 g E. 426 g
Solved
Show answers
More tips
- S Style and Beauty Choosing a Hair Straightener: Specific Criteria to Consider...
- F Family and Home How to Remove Tar Stains: Tips and Recommendations from Experts...
- F Family and Home How to Remove Fading from Clothes: Tips and Tricks...
- S Sport How to Do a Jumping Split...
- H Health and Medicine How Did Inna Lose Weight on Dom 2?...
- F Family and Home How to Properly Fold Napkins in a Napkin Holder?...
- F Food and Cooking How to Set Up Ventrilo - The Ultimate Guide...
- S Science and Technology How to Make a Homemade Smoker: The Ultimate Guide...
- A Auto and Moto Battle for the Relocation of The Cherkizovsky Market: Who Won?...
- C Computers and Internet How Do You Refill Cartridges?...
Answers on questions: Chemistry
- P Physics A 100.0-kg bakery sign hangs from two thin cables as shown. What is the tension in each cable?...
- M Mathematics Determine the conclusion of the statement: an actor will be paid more if he wins an oscar...
- E English Which statement best describes how the connotation of the word pushy affects the passage s tone?...
Ответ:
A. 266g/mol
Explanation:
A colligative property of matter is freezing point depression. The formula is:
ΔT = i×Kf×m (1)
Where:
ΔT is change in temperature (0°C - -0,14°C = 0,14°C)i is Van't Hoff factor (1 for a nonelectrolyte dissolved in water), kf is freezing point molar constant of solvent (1,86°Cm⁻¹) and m is molality of the solution (moles of solute per kg of solution). The mass of the solution is 816,0g
Replacing in (1):
0,14°C = 1×1,86°Cm⁻¹× mol Solute / 0,816kg
0,0614 = mol of solute.
As molar mass is defined as grams per mole of substance and the compound weights 16,0g:
16,0g / 0,0614 mol = 261 g/mol ≈ A. 266g/mol
I hope it helps!
Ответ:
2.44 K IS THE TEMPERATURE OF THE GAS
Explanation:
PV = nRT
P = 0.5 atm
V = 2 L
n = 5 moles
R = 0.082 L atm mol^-1 K^-1
T = ?
Substituting for T in the equation, we obtain:
T = P V / nR
T = 0.5 * 2 / 5 * 0.082
T = 1 / 0.41
T = 2.44 K
The temperature of the gas is 2.44 K