Chemistry: When 2.0 x 10-2 mole of nicotinic acid (amonoprotic acid) is dissolved in 350 ml of water, the ph is 3.05.what is the ka of nicotinic acid?

When 2.0 x 10-2 mole of nicotinic acid (amonoprotic

Ответ:

gerardogonzale362

02.01.2022

Chemistry

Ka of nicotinic acid = $1.41 \times 10^{-5}$

Explanation:

pH = 3.05

pH = -log [H^+]

$H^+ = (10)^{-3.05}=0.00089125 M$

No. of mol of nicotinic acid = $2.0 \times 10^{-2}$

Volume of water = 350 mL = 0.0350 L

Molarity = $\frac{Moles}{Volume\ in\ L}$

Molarity = $\frac{2.0 \times 10^{-2}}{0.350} = 0.05714\ M$

Nicotinic acid dissoctates as:

$HA \rightarrow H^+ + A^-$

[H+] = 0.00089125 M

[A-] = 0.00089125 M

[HA} at equilibium = 0.05714 - 0.00089125 = 0.05624875 M

$Ka = \frac{[H^+][A^-]}{[HA]}$

$Ka = \frac{(0.00089125)^2}{0.05624875} = 1.41 \times 10^{-5}$

0,0(0 оценок)

Ответ:

RayeK168

02.11.2021

Chemistry

B. organ

Explanation:

Smooth muscle is found in the walls of hollow organs like your intestines and stomach. They work automatically without you being aware of them. Smooth muscles are involved in many 'housekeeping' functions of the body.

0,0(0 оценок)

When 2.0 x 10-2 mole of nicotinic acid (amonoprotic
acid) is dissolved in 350 ml of water, the ph is 3.05.what is the
ka of nicotinic acid?

Ответ:

Ответ:

Ask your question to the AI advisor

More tips

Answers on questions: Chemistry

Ask an AI advisor a question