When a container is filled with 8 moles of H2,7 moles of O2, and 2 mole of N2, the pressure in the container is 10.6 atm. Find Po2

ΔG = -24.7kJ/mol

Explanation:

ΔG° of

Pb2+(aq) + 2Br-(aq) ⇄ PbBr2(s)

is:

ΔG° PbBr2 - (2*ΔG°Br- + ΔG°Pb2+)

-261.9kJ/mol - (2*-104.0kJ/mol + -24.4kJ/mol) =  

-29.5kJ/mol

ΔG of the reaction is:

ΔG = ΔG° + RT lnQ

Where R is gas constant (8.314x10⁻³kJ/molK)

T is absolute temperature (20°C + 273.15 = 293.15K)

Q is reaction quotient = 1 / [Pb²⁺][Br⁻]²

Replacing:

ΔG = -29.5kJ/mol + 8.314x10⁻³kJ/molK*293.15K ln(1 / [Pb²⁺][Br⁻]²)

ΔG = -29.5kJ/mol + 8.314x10⁻³kJ/molK*293.15K ln(1 / [0.247M][0.758M]²)