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seimdakota
13.11.2020 •
Chemistry
When a lit match is touched to the wick of a candle, the candle begins to burn. When the match is removea
the candle continues to burn because the match
A supplies the energy to start the reaction
B is part of the rate determing step
C makes the reaction need less energy to start
behaves as a catalyst
Solved
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Ответ:
(1) Cl₂ is the limiting reactant.
(2) 8.18 g
Explanation:
2Na(s) + Cl₂(g) → 2NaCl(s)First we convert the given masses of reactants into moles, using their respective molar masses:
Na ⇒ 12.0 g ÷ 23 g/mol = 0.522 mol NaCl₂ ⇒ 5.00 g ÷ 70.9 g/mol = 0.070 mol Cl₂0.070 moles of Cl₂ would react completely with (2 * 0.070) 0.14 moles of Na. There are more Na moles than that, so Na is the reactant in excess while Cl₂ is the limiting reactant.
Then we calculate how many moles of NaCl are formed, using the limiting reactant:
0.070 mol Cl₂ *Finally we convert NaCl moles into grams:
0.14 mol NaCl * 58.44 g/mol = 8.18 g