When aqueous solutions of chromium(II) iodide and sodium phosphate are combined, solid chromium(II) phosphate and a solution of sodium iodide are formed. The net ionic equation for this reaction is:

3 Cr²⁺(aq) + 2 PO₄³⁻(aq) ⇄ Cr₃(PO₄)₂(s)

Explanation:

When aqueous solutions of chromium(II) iodide and sodium phosphate are combined, solid chromium(II) phosphate and a solution of sodium iodide are formed. The molecular equation is:

3 CrI₂(aq) + 2 Na₃PO₄(aq) ⇄ Cr₃(PO₄)₂(s) + 6 NaI(aq)

The full ionic equation includes all the ions and the molecular species.

3 Cr²⁺(aq) + 6 I⁻(aq) + 6 Na⁺(aq) + 2 PO₄³⁻(aq) ⇄ Cr₃(PO₄)₂(s) + 6 Na⁺(aq) +         6 I⁻(aq)

The net ionic equation includes only the ions that participate in the reaction and the molecular species.

3 Cr²⁺(aq) + 2 PO₄³⁻(aq) ⇄ Cr₃(PO₄)₂(s)

The correct option is ΔABC ≅ ΔFED by SAS

Step-by-step explanation:

Looking at the given diagram,

Side AC = Side DF = 3.2

Side AB = Side FE = 4 units

Angle A = angle F = 72 degrees

Since two sides and one angle are equal, then triangle FED = triangle ABC by SAS(side angle side)

This makes the ratios possible

AB/FE = AC/DF

The HL given means hypotenuse leg. It will not hold because the triangles are not right angle triangles.