Chemistry: Which diatomic molecule is formed when the two atoms share six electrons? (1) h2 (2) n2 (3) o2 (4) f2

Which diatomic molecule is formed when the two

Ответ:

logan541972

17.04.2022

Chemistry

$\large \boxed{\text{22 g methane; 60 g oxygen}}$

Explanation:

1. Gather the information

We will need a chemical equation with masses and molar masses, so, let's gather all the information in one place.

Mᵣ: 16.04 32.00 44.01

CH₄ + 2O₂ ⟶ CO₂ + 2H₂O

m/g: 60

1. Moles of CO₂

$\text{Moles of CO}_{2} = \text{60 g CO}_{2} \times \dfrac{\text{1 mol CO}_{2}}{\text{44.01 g CO}_{2}} = \text{1.36 mol CO}_{2}$

2. Mass of CH₄

(a) Moles of CH₄

$\text{Moles of CH}_{4} = \text{1.36 mol CO}_{2} \times \dfrac{\text{1 mol CH}_{4}}{\text{1 mol CO}_{2}} = \text{1.36 mol CH}_{4}$

(b) Mass of CH₄

$\text{Mass of CH}_{4} = \text{1.36 mol CH}_{4} \times \dfrac{\text{16.04 g CH}_{4}}{\text{1 mol CH}_{4}} = \textbf{22 g CH}_{4}\\\\\text{The mass of CH$_{4}$ required is $\large \boxed{\textbf{22 g}}$}$

3. Mass of O₂ required

(a) Moles of O₂

$\text{Moles of O}_{2} = \text{1.36 mol CO}_{2} \times \dfrac{\text{2 mol O}_{2}}{\text{1 mol CO}_{2}} = \text{2.73 mol O}_{2}$

(b) Mass of O₂

$\text{Mass of O}_{2} = \text{2.73 mol O}_{2} \times \dfrac{\text{32.00 g O}_{2}}{\text{1 mol O}_{2}} = \textbf{60 g O}_{2}\\\\\text{The mass of O$_{2}$ required is $\large \boxed{\textbf{60 g}}$}$

0,0(0 оценок)

Which diatomic molecule is formed when the
two atoms share six electrons?
(1) h2
(2) n2
(3) o2
(4) f2

Ответ:

Ответ:

Ask your question to the AI advisor

More tips

Answers on questions: Chemistry

Ask an AI advisor a question