Which equation is set up correctly to determine the volume of a 3.2 mole sample of oxygen gas at 50°c and 101.325 kpa?

a v=(3.2 mol)(8.314 l⋅kpa/k⋅mol)(323 k)101.325 kpa

b v=(3.2 mol)(8.314 l⋅kpa/k⋅mol)(50∘c)1 atm

c v=(8.314 l⋅kpa/k⋅mol)(50∘c)(3.2 mol)(101.325 kpa)

d v=(3.2 mol)(8.314 l⋅kpa/k⋅mol)(1 atm)(323 k)

N = 3.2 moles, T = 50 + 273 = 323 K, P = 101.325 kPa,  R = 8.314 L.kPa/K.mol 

PV = nRT

V = nRT / P           substituting.

V = (3.2 mole)(8.314 L.kPa/K.mol )(323 K) / (101.325 kPa)

That is the answer, but it is not among the options you provided. Check your options properly.

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