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kenzie9493
26.12.2019 •
Chemistry
Which of the following gives the molarity of a 17.0% by mass solution of sodium acetate, ch 3coona (molar mass = 82.0 g/mol) in water? the density of the solution is 1.09 g/ml. a. 2.26 × 10^-6 m b. 0.207m c. 2.07m d. 2.26m e. 2.72m
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Ответ:
The molarity of this solution is 2.26 M (option D)
Explanation:
Step 1: Data given
Mass % = 17%
Molar mass of CH3COONa = 82.0 g/mol
Density of the solution = 1.09 g/mL
Step 2:
Assume the mass of the solution is 1.00 gram
⇒ 17.0 % CH3COONa = 0.17 grams
⇒ 83.0 % H2O = 0.83 grams
Step 3:
Density = 1.09 g/mL
Volume of the solution = total mass / density of solution
Volume of solution : 1.00 grams / 1.09 g/mL
Volume of the solution = 0.917 mL = 0.000917 L
Step 4: Calculate number of moles of CH3COONa
Number of moles = Mass / molar mass
Number of moles CH3COONa = 0.170 grams / 82.0 g/mol
Number of moles = CH3COONa = 0.00207 moles
Step 5: Calculate molarity
Molarity = moles / volume
Molarity solution = 0.00207 / 0.000917 L
Molarity solution = 2.26 mol/L = 2.26 M
The molarity of this solution is 2.26 M (option D)
Ответ:
may be 25g...
aap try kro na hum bta dege answer.