Which of the following processes would you expect to have a negative value for entropy? nacl(s) na+(aq) + cl- (aq) h2o(s) h2o(l) nacl(s) nacl(l) 2 al(s) + 3br2(l) 2albr3(s) c2h5oh(l) c2h4(g) + h2o(g)

Explanation:  Entropy is the measure of randomness or disorder of a system. A system has positive value of entropy if the disorder increases and a system has negative value of entropy if the disorder decreases.

Solids have highest order followed by liquids and gases have least order.

1.

As a solid is dissociating into ions, the randomness is increasing and the entropy is also increasing.

2.

As solid is changing to liquid phase, the randomness is increasing and the entropy is also increasing.

3.

As solid is changing to liquid phase, the randomness is increasing and the entropy is also increasing.

4.

As one solid and liquid is changing into solid only, the randomness is decreasing and the entropy is also decreasing.

5.

As liquid is changing to gaseous form,  the randomness is increasing and the entropy is also increasing.

see below

Step-by-step explanation:

A.  f(x) = 4x^2 - 7x - 15

We need the numbers to multiply to- 15

1*15  and 3*5  

One of the terms multiplies by 4 (or 2)

Try 4 first

4*-3 +5 = -7   That works

-3+5 = -15

f(x) = (4x+5)(x-3)

B.  We want the x intercepts so set equal to 0

0 = (4x+5)(x-3)

Using  the zero product  property

0 = 4x+5    x-3 =0

-5 = 4x           x=3

-5/4 =x            x=3

C  End behavior

Let x be negative infinity

The function is dominate by 4x^2

f(-∞) = 4 ( -∞) ^2 = 4 (∞) = ∞  

At negative infinity the functions goes to infinity

Let x be  infinity

The function is dominate by 4x^2

f(∞) = 4 ( ∞) ^2 = 4 (∞) = ∞  

At  infinity the functions goes to infinity

Part D:

We know the zeros at 3 and -5/4

We know the vertex is at  halfway between the zeros

(3 -5/4) /2 =  7/4 /2 = 7/8

Since the parabola opens up (The coefficient of the x^2 term is positive), we know we have a minimum.

f(7/8) = 4 (7/8)^2 -7(7/8) -15 = 4(49/64) -1/8 -15 =-289/16

We know the minimum the zeros and the end behavior, we can graph the functions