Which will diffuse fast cl2,f2, or he

He

Explanation:

According to the Graham's law of effusion or diffusion, the rate of diffusion of a fixed mass of a gas is inversely proportional to the square root of its density.Therefore, the lighter the gas, the higher the rate of effusion rate since the effusion rate of a gas is inversely proportional to the square root of its molecular mass.In this case, Helium gas is the lightest and thus, it will diffuse faster compared to the other gases.

A. C₃H₄N

Explanation:

Firstly, we need to calculate the no. of moles of C, H, and N using the relation:

no. of moles = mass/molar mass.

∴ no. of moles of C = mass/molar mass = (90.0 g)/(12.0 g/mol) = 7.5 mol.

∴ no. of moles of H = mass/molar mass = (11.0 g)/(1.0 g/mol) = 11.0 mol.

∴ no. of moles of N = mass/molar mass = (35.0 g)/(14.0 g/mol) = 2.5 mol.

We should get the mole ratio of each atom by dividing by the lowest no. of moles (2.5 mol of N).

∴ the mole ratio of C: H: N = (7.5 mol/2.5 mol): (11.0 mol/2.5 mol): (2.5 mol/2.5 mol) = (3: 4.4: 1) ≅ (3: 4: 1).

So, the empirical formula is: A. C₃H₄N.