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Explanation:

Explanation:

C₆H₁₂O₆       +      60₂     =     6H₂0     +     6CO₂.

1 mole              6 mole

molecular weight of C₆H₁₂O₆ = 180 g

molecular weight of oxygen = 32 g

1 gram of glucose = 1 / 180 = 5.55 x 10⁻³ moles

1 gram of oxygen = 1 / 32 = 31.25 x 10⁻³ moles

1 mole of glucose reacts with 6 moles of oxygen

5.55 x 10⁻³ moles of glucose will react with 6 x 5.55 x 10⁻³ moles of oxygen

= 33.30 x 10⁻³ moles of oxygen .

But oxygen available = 31.25 x 10⁻³ moles

So available oxygen is less than required .

Hence oxygen is the limiting reagent .

b ) is the right option .