With what volume of 5.00 m hf will 4.72 g of calcium hydroxide react completely, according to the following reaction? 2hf + ca(oh)2 → caf2 + 2h2o

 The volume  of 5.00 M  HF that will react with 4.72  g   of  calcium hydroxide  is 0.0256 L

  calculation

2HF   + Ca(OH)₂ →  CaF₂ + 2H₂O

Step 1:  find the  moles  of Ca(OH)₂

moles= mass÷  molar mass

from periodic  table the molar mass of Ca(OH)₂  = 40 +( 16+1)₂= 74 g/mol

moles =  4.72 g÷  74 g/mol =0.0638   moles

Step  2:  use the  moles ratio to determine the  moles of Hf

from the equation above HF: Ca(OH)₂  is 2:1

therefore the moles of HF = 0.0638 moles x 2/1 =0.1276 moles

Step 3: find   the  volume  of HF

volume=moles /molarity

molarity =5.00 M = 5.00 mol/L

=0.1276  moles / 5.00 mol/l =0.0256 L