Write a balanced net ionic equation to show why the solubility of ZnCO3 (s) increases in the presence of a strong acid and calculate the equilibrium constant for the reaction of this sparingly soluble salt with acid.Consider only the FIRST STEP in the reaction with strong acid. Be sure to specify states such as (aq) or (s).

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Ответ:

ashtonbillups

12.09.2021

Chemistry

Answer : The mass of oxygen required are, 56.448 grams

Explanation : Given,

Mass of glucose = 53 g

Molar mass of glucose = 180.156 g/mole

Molar mass of O_2 = 32 g/mole

First we have to calculate the moles of $C_6H_{12}O_6$ .

$\text{Moles of }C_6H_{12}O_6=\frac{\text{Mass of }C_6H_{12}O_6}{\text{Molar mass of }C_6H_{12}O_6}=\frac{53.0g}{180.156g/mole}=0.294moles$

Now we have to calculate the moles of O_2 .

The balanced chemical reaction will be,

$C_6H_{12}O_6(aq)+6O_2(g)\rightarrow 6CO_2(g)+6H_2O(l)$

From the balanced chemical reaction, we conclude that

As, 1 mole of $C_6H_{12}O_6$ react with 6 moles of O_2

So, 0.294 mole of $C_6H_{12}O_6$ react with $0.294\times 6=1.764$ mole of O_2

Now we have to calculate the mass of O_2 .

$\text{Mass of }O_2=\text{Moles of }O_2\times \text{Molar mass of }O_2$

$\text{Mass of }O_2=(1.764mole)\times (32g/mole)=56.448g$

Therefore, the mass of oxygen required are, 56.448 grams

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