Chemistry: You are using a standardized 0.1250 M solution of sodium hydroxide to determine the concentration of sulfuric acid. After pipetting 10.00 mL of the H2SO4 into your flask you find that you use 19.22 mL of your NaOH solution to reach the endpoint. No, wait... I mean What is the concentration of the sulfuric acid? H2SO4 + 2NaOH --- Na2SO4 + 2HOH

You are using a standardized 0.1250 M solution of

Ezekielcassese

20.01.2022

Thus the concentration of the sulfuric acid is 0.1201 M

Explanation:

$H_2SO_4+2NaOH\rightarrow Na_2SO_4+2H_2O$

To calculate the concentration of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is H_2SO_4

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is NaOH.

We are given:

$n_1=2\\M_1=?\\V_1=10.00mL\\n_2=1\\M_2=0.1250M\\V_2=19.22mL$

Putting values in above equation, we get:

$2\times M_1\times 10.00=1\times 0.1250\times 19.22\\\\M_1=0.1201M$

Thus the concentration of the sulfuric acid is 0.1201

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