Anew network administrator has been asked to verify the metrics that are used by eigrp on a cisco device. which two eigrp metrics are measured by using static values on a cisco device? (choose two.)a) loadb) reliabilityc) bandwidthd) mtue) delay

C & E

Explanation:

Metric are parameters used in a dynamic routing protocol to determine a network path. Dynamic routing protocols are protocols configured to a router to enable dynamic learning of network paths in interconnected networks.

There are various types of dynamic routing protocols, they are, RIP, EIGRP, OSPF, IS-IS, BGP etc.

The EIGRP uses various metrics to determine network paths, they are bandwidth, delay, load, Reliability etc.

The reliability and load metrics values are dynamically updated over a period of time, while the bandwidth and delay are static values, but the MTU is not a metric used in EIGRP.

Step-by-step explanation:

In each of the situations, probabilities have been assigned to the outcomes of the experiment. Some are legitimate (they correctly satisfy the rules of probability) while others are not.

(A) We know that a die has 6 faces, each with a dot or spot representing numbers 1 to 6. The probabilities assigned to the outcomes 1, 3, 4, and 6 are WRONG. They do not satisfy the law of probability. Each outcome has an equal probability or chance of occurring. There are 6 possible outcomes and each stands a 1/6 chance of occurring when the die is rolled. Hence the probability values assigned to the occurrence of 2 and the occurrence of 5 are correct!

(B) We know the standard French playing-cards has 52 cards in a deck or pack. There are 13 clubs, 13 hearts, 13 diamonds and 13 spades, altogether 52 cards. So in a shuffled deck of cards, the probability that a dealt card will be clubs is 13/52. The probability that it will be hearts is 13/52. The probability that it will be diamonds is 13/52 and the probability that it will be spades is 13/52! Add up the probabilities and they will equal 1.

So the probabilities assigned to these 4 possible outcomes in this question are WRONG.

(C) Now, there is no indication of the total number of students in this college. We need figures on the

- number of males

- number of females

- number of part time students

- number of full time students

Without this information, we cannot ascertain the probabilities required.

Hence, the probability assignments to the 4 groups of college students are WRONG.