The Digital Millennium Copyright Act: a. makes it a criminal offense to create programs to circumvent encoded copyrighted materials. b. does not impose liability on those who provide Internet access to employees. c. does not impose liability for circumvention of encoding of copyrighted materials for personal use. d. both b and c e. none of the above

Liability under DMCA:

-Key is circumvention or marketing of a prohibited device, not whether the circumventing act resulted in copyright infringement.

-Violations of the anti-circumvention provisions are NOT copyright infr

Cases when Circumvention is Allowed :

1) Computer programs and video games distributed in obsolete formats (converting floppy to CD so it's useable)

2) For the purpose or preservation of archival reproduction by a library or archive

3) Computer programs protected by damaged and obsolete access control mechanisms (aka dongles)

4) Literary works in e-book formats in order to enable the use of read aloud programs and screen readers for the blind and disabled

5) Computer program in cell phones for sole purposes of lawfully connecting to wireless telephone communications network

6) Sound recordings and AV works on CDs that contain access control measures that create or exploit security flaws on PCs for the sole purpose of investigating, testing, or correcting such flaws

#include <stdio.h>

int getElement(int arr[], int size) {

   int largest2, largest = 0;

   for(int i=0; i<size; i++)

   {

       if(arr[i] > arr[largest])

       {

           largest = i;

       }

   }

   if(largest != 0)

       largest2 = 0;

   else

       largest2 = size - 1;

   for(int i=0; i<size && i != largest ;i++)

   {

       if(arr[i] > arr[largest2])

           largest2 = i;

   }

   return arr[largest2];

}

printArray(int arr[], int size) {

   printf("The array is: ");

   for(int i=0; i<size; i++)

   {

       printf("%d ", arr[i]);

   }

   printf("\n");

}

int main()

{

   int arr[5] = {30, 20, 5, 10, 24};

   printArray(arr, 5);

   printf("Second largest number is: %d", getElement(arr, 5));

   return 0;

}

Explanation:

Since you did not provide any code, I wrote it from the scratch. I also added the main function for you to check the result.

printArray function basically prints the element of the array

getElement function:

- Declare the two variables to hold the value for largest and second largest

- Inside the first loop, check if there is any number that is greater than largest, if yes, assign it to largest

- Inside the second for loop, check if there is any number that is greater than largest2, if yes, assign it to largest2 (Be aware that the largest we found in the first loop is excluded)

- Return the second largest

* Notice that we were able to apply this solution since the numbers are unique.