Use a karnaugh map to find a minimum sum of products for the following function. show the k-map, write the minimal boolean expression, and draw the logic diagram
f= a'b'cd + a'b'cd' + bd + ab'cd

#include <stdio.h>

int main()

{

   int A[10];

   int sum = 0;

   printf("Enter array elements\n");

   for (int i = 0; i < 10 ; i++)

       scanf("%d", &A[i]);

   for (int i = 0; i < 10 ; i++) {

       if (i % 2 ==1)

           sum += A[i];

   }

   printf("Sum of odd indexed elements: %d \n", sum);

   printf("Array in reverse order: ");

   for (int i = 9; i >= 0; i--)

     printf("%d ", A[i]);

   return 0;

}

Explanation:

Declare the array and sum variable

Ask user for the array elements and put them in the array using for loop

Calculate the sum of the numbers that are at odd index, check if the index is odd using modulo operator

Print the array in reverse order using for loop, start the index from 9 and go until 0, so that it will print from back