Engineering: A three-point bending test is performed on a glass specimen having a rectangular cross section of height d 5 mm (0.2 in.) and width b 10 mm (0.4 in.); the distance between support points is 45 mm (1.75 in.). Compute the flexural strength if the load at fracture is 290 N (65 lb

A three-point bending test is performed on a glass

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yhhh

26.06.2020

Engineering

The flexural strength of a specimen is = 78.3 M pa

Explanation:

Given data

Height = depth = 5 mm

Width = 10 mm

Length L = 45 mm

Load = 290 N

The flexural strength of a specimen is given by

$\sigma = \frac{3 F L}{2 bd^{2} }$

$\sigma = \frac{3(290)(45)}{2 (10)(5)^{2} }$

$\sigma =$ 78.3 M pa

Therefore the flexural strength of a specimen is = 78.3 M pa

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Hiadamcom

10.04.2021

Engineering

A Orange juice contains particles of solid (pulp) as well as liquid; it is not chemically pure. C Because its composition is not uniform throughout, orange juice is a heterogeneous mixture

Explanation:

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A three-point bending test is performed on a glass specimen having a rectangular cross section of height d 5 mm (0.2 in.) and width b 10 mm (0.4 in.); the distance between support points is 45 mm (1.75 in.). Compute the flexural strength if the load at fracture is 290 N (65 lb

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