Engineering: Acoil of wire 8.6 cm in diameter has 15 turns and carries a current of 2.7 a. the coil is placed in a magnetic field of 0.56 t. what is the magnitude of the maximum torque that can be applied to the coil by the magnetic field?

Acoil of wire 8.6 cm in diameter has 15 turns and

abolton04

14.03.2022

Explanation:

it is given that diameter = 8.6 cm

$radius =\frac{8.6}{2}=4.3\ cm=4.3\times 10^{-2}\ m$

current =2.7 ampere

number of turns = 15

$area =\pi r^2=3.14\times \left ( 4.3\times 10^{-2} \right )^{2}=0.005806 m^{2}$

magnetic field =0.56 T

maximum torque= BINASINΘ for maximum torque sinΘ=1

so maximum torque==0.56×2.7×0.005806×15=0.13174 Nm

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tiny2007

03.02.2020

idk

Explanation:

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