an 8 N weight is placed at one end of a meterstick. a 10N weight is placed at the other end. where should the fulcrum be placed to have the meterstick balanced?

The fulcrum should be placed 0.44 from the 12 N weight or 0.56 m from the 8 N weight.

Explanation:

Given:

= 8 N

= 10 N

Since the meter stick has a length of 1 m, and

Let = x

Let = 1 - x

Question:

Where should the fulcrum be placed to have the meterstick balanced?

Equation:

For the system to be balanced, the product of the weight and distance of the objects on opposite sides should be equal. This is is shown by the equation:

where: w - weight

d - distance from the fulcrum

Solution:

Substituting the value of and in the formula,

(8 N)(x) = (10 N)(1 m - x)

x(8 N) = (10 N)m - x(10 N)

x(8 N) + x(10 N) = (10 N) m

x(18 N) = 10 N

x =

x = 0.56

Solve for

= x

= 0.56 m

Solve for

= 1 m - x

= 1 m - 0.56 m

= 0.44 m

Final The fulcrum should be placed 0.44 from the 12 N weight or 0.56 m from the 8 N weight.

Hey there!

Explanation:The ruler is pointing on Hope it help you