Engineering: An airliner is flying at 34,000 ft cruise altitude on a standard day. calculate the pressure difference between the cabin and the atmosphere if the cabin is pressurized to an altitude of 8,000 ft. assume standard day temperature in the cabin

An airliner is flying at 34,000 ft cruise altitude - id340002726105, erickasmith1988

Ответ:

jojo8617

04.01.2022

Engineering

$\Delta P=61,952.8\ lb/ft^2$

Explanation:

Given

Airline flying at 34,000 ft.

Cabin pressurized to an altitude 8,000 ft.

We know that at standard condition ,density of air

$\rho =0.074\ lb/ft^3$

We know that pressure difference

ΔP=ρ g ΔZ

Here ΔZ=34,000-8,000 ft

ΔZ=26,000 ft

$g= 32.2\ ft/s^2$

ΔP=0.074 x 32.2 x 26,000

$\Delta P=61,952.8\ lb/ft^2$

So pressure difference will be $\Delta P=61,952.8\ lb/ft^2$ .

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Ответ:

csorensen

20.02.2023

Engineering

I don’t think it is because it is to big and heavy for the ground to support and the bridge will sink in a short amount of time. they should think about using better materials on the bridge. they should also locate it in a better area.

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An airliner is flying at 34,000 ft cruise altitude on a standard day. calculate the pressure difference between the cabin and the atmosphere if the cabin is pressurized to an altitude of 8,000 ft. assume standard day temperature in the cabin

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