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21ltilley
05.10.2019 •
Engineering
The flow rate of liquid metal into the downsprue of a mold = 0.7 l/sec. the cross-sectional area at the top of the sprue = 750 mm^2, and its length = 185 mm. what area should be used at the base of the sprue to avoid aspiration of the molten metal (mm^2)?
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Ответ:
367.43 mm²
Explanation:
Given:
Flow rate, Q = 0.7 L/s
1000 L = 1 m³ = 10⁹ mm³
thus,
1 L = 10⁶ mm³
Therefore,
Q = 0.7 × 10⁶ mm³/s
Cross-sectional area at the top of the sprue = 750 mm²
Length of the sprue = 185 mm
Now,
Velocity =![\sqrt{2gh}](/tpl/images/0289/6788/66350.png)
where, g is the acceleration due to gravity = 9.81 m/s²
h is the height through which flow is taking place = 185 mm = 0.185
thus,
Velocity =![\sqrt{2\times9.81\times0.185}](/tpl/images/0289/6788/d43d9.png)
or
velocity = 1.9051 m/s = 1905.1 mm/s
Also,
Q = Area × Velocity
thus,
0.7 × 10⁶ = Area × 1905.1
or
Area = 367.43 mm²
Ответ:
thanks!
Explanation: