josmanu235
17.09.2019 •
English
Abody moving with uniform acceleration has a velocity of 15.3 cm/s when its x coordinate is 4.3 cm. if its x coordinate 1.72 s later is −2.32 cm, what is the x-component of its acceleration? answer in units of cm/s 2 .
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Ответ:
a=-22.266cm/s^2
Explanation:
A body that moves with constant acceleration means that it moves in "a uniformly accelerated movement", which means that if the velocity is plotted with respect to time we will find a line and its slope will be the value of the acceleration, it determines how much it changes the speed with respect to time.
When performing a mathematical demonstration, it is found that the equations that define this movement are as follows.
Vf=Vo+a.t (1)
{Vf^{2}-Vo^2}/{2.a} =ΔX(2)
X=Xo+ VoT+0.5at^{2} (3)\\
Where
Vf = final speed
Vo = Initial speed
T = time
A = acceleration
X = displacement
In conclusion to solve any problem related to a body that moves with constant acceleration we use the 3 above equations and use algebra to solve
FOR THIS PROBLEM
X=-2.32cm
Xo=4.3cm
Vo=15.3cm/s
t=1.72s
WE USE THE ECUATION 3
a=(X-Xo-Vot)2/t^2
a=(-2.32-4.3-15.3x1.72)2/1.72^2
a=-22.266cm/s^2
Ответ:
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