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tristanf123
06.05.2020 •
English
For some hypothetical metal the equilibrium number of vacancies at 750 degrees Celsius is 2.8x1024 m^-3. If the density and atomic weight of this metal are 5.60 g/cm3 and 65.6 g/mol, respectively, calculate the fraction of vacancies for this metal at 750 degress Celsius.
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Ответ:
1.90× 10^4
Explanation:
The ratio of the equilibrium number of vacancies given in the problem statement (Nv= 2.3 x 10^25m^3) and the value of N is obtained using this formula N=NAp/A .
Thus;
The fraction of vacancies is equal to the Nv/Nratio.
Firstly the value of N is obtained with N=NAp/A
=( (6.022 x 10^23 atoms/mol)(5.60 g/cm3 )(10^6cm^3/m^3) )/65.6 g/mol
= 2.83 x 10^28atoms/m^3
The fraction of vacancies is Nv/Nratio:
Nv = 2.8x10^24 m^-3.
N = 2.83×10^28atoms/m^3
= 1.90× 10^4
Ответ:
a) Yes, because it includes key ideas from the beginning, middle, and end, and it explains the conflict and the resolution.
Explanation: