The united states views chavez as a threat because a- of his strong relationship with iran and cuba b- of his verbal confrontation with condoleeza rice c- of his ability to monopolize foreign oil reserves d- of his proactive approach in developing weapons of mass destruction

Answering the question, the United States views Chavez as a threat because of his strong relationship with Iran and Cuba.  

Chavez was against most of the foreign policy of the United States. He criticized the United States' economic and foreign policy. Chavez was also not in support of the United States as regards the removal of Haitian President Jean-Bertrand Aristide.

Chavez's relationship with Cuba and Fidel Castro in regards to trading affected the United States US policy that isolated Cuba.

Also, Chavez's position on OPEC price hawk showed he was a threat to the United States because his stance to support lower oil output and higher prices affected the prices of petroleum in the United States of America.  

Chavez, in his capacity as one of the OPEC directors in 2000 toured all the OPEC countries and also met with Saddam Hussein. He was indeed the first head of states to meet with Hussein after the Gulf war. Chavez's meeting with Saddam Hussein was highly controversial and also was against the interest of the United States.

All his actions when he was the president of Venezuela show his hatred for the United States. He was always criticizing the administration of President George W. Bush

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I will answer in English.

Ok, we know that the acceleration is a = 18m/s^2, and we have that the initial velocity and position are both zero. (because it starts at rest)

then we have:

a(t) = 18m/s^2

for the velocity, we integrate over time (because the initial velocity is equal to zero we do not have any integration constant)

v(t) = (18m/s^2)*t

for the position we integrate again over time, and again, we do not have any integration constant

p(t) = (1/2)(18m/s^2)*t^2 = (9m/s^2)*t^2

a) The speed at t= 3s can be found by replacing t = 3s in the velocity equation.

v(3s) =  (18m/s^2)*3s = 54m/s

b) the distance traveled by this time can be found by replacing t = 3s in the position equation.

p(3s) =(9m/s^2)*(3s)^2 = 81 m

c) first, we need to find what is the time when the position is equal to 200m.

p(t) = 200m =  (9m/s^2)*t^2

√(200/9) s = t = 4.7s

Now we replace that time in the velocity equation and we get:

v (4.7s) =   (18m/s^2)*4.7s = 84.6m/s

d) ok, to do this we know that.

1 hour has: 60*60 = 3600 seconds.

then we have the transformation  k = 1h/3600s

1 km has 1000 meters.

then we have the transformation c = 1km/1000m

so we have that:

84.6m/s = 84.6m/s*(c/k) = 84.6*(3600/1000)km/h = 304.56 km/h