mikey8510
21.01.2021 •
Mathematics
05.01 Solving Systems of Equations Graphically Algebra I Intervention- Vandecar/Module 05: Systems of Equations 1. (05.01) The graph of a system of parallel lines will have no solutions. (1 point) 1. Always
2.Sometimes
3. Never
Solved
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Ответ:
c²=b²+a²-2ba cosC
Right triangle = 90 degrees
cosine 90 degrees = 0
c²=28²+15²-2×28×15×0
c²=28²+15²
c=√1009
c=31.8 in