hdjehd
05.02.2020 •
Mathematics
1. a person preparing medicine wants to convert 15% alcohol solution into 32% alcohol
solution. find how much pure alcohol should he mix with 400 ml of 15% alcohol
solution to obtain it.
pls give me an answer to this. i will give 10 points.
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Ответ:
100mL
Step-by-step explanation:
A 15% alcohol solution contains 15mL alcohol in 100mL solution
In 400ml there will be 400mL·15/100 = 6,000mL/100 = 60mL alcohol
Let the volume of pure alcohol to be added V.
In the new solution there will be (60 + V)mL alcohol
And the total volume will be (400 + V)mL
Concentration required 32% = 0.32
Concentration = (60 + V)mL/(400 + V)mL = 0.32
60mL + VmL = 0.32(400 + V)mL
60mL + VmL = 128mL + V·*0.32mL
VmL - V·0.32mL = 128mL - 60mL = 68mL
V(1 - 0.32)mL = 68mL
V·0.68mL = 68mL
VmL = 68mL/0.68 = 100mL ► alcohol volume to be added
Answer : 100mL
Verification
New solution
There will be 400mL + 100mL = 500mL total volume
There will be 60mL alcohol + 100mL alcohol = 160mL alcohol
The concentration will be 160mL/500mL = 0.32 = 32%
Ответ:
I can't cause i dont have a mother ._.
Step-by-step explanation: