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annabel11
24.06.2020 •
Mathematics
1. A ship left port A heading for port B. It sailed due East for 40 miles. It then sailed due North
for 30 miles. Find:
i. The distance between the two ports
ii. The bearing of port B as measured from port A
iii. The bearing of port A as measured from port B
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Ответ:
i)Distance between port A and Port B is 500 miles.
ii)Bearing of port B from A= N 53.13°E
iii)Bearing of port A from B= S 53.13°W
Step-by-step explanation:
The movement of the ship from port A to port B formed a right angle triangle.
To calculate the distance from port A to post B,
Let distance AB = X
AC = y
CB= z
X² = y² + z²
x² = 40² + 30²
= 1600+900
= 2500
X²= 2500
X= 50
Distance between port A and Port B is 500 miles.
Angle at A
30/sin a= 50/sin 90
Sin a = 30/50
a= sin^-1( 0.6)
a= 36.87°
Bearing of port B from A
90-36.87= 53.13
Bearing of port B from A= N 53.13°E
Angle at B
=180-(90+36.87)
b= 53.13°
Bearing of port A from B= S 53.13°W
Ответ:
Friday plus Saturday : 40 + 30 = 70
70 ÷ 160 = 0.4375
43.75 %