Mathematics: 1.) a.) tan 50° b.) cot 50° c.) sin 50° d.) cos 50° e.) cot 50°

1.) a.) tan 50° b.) cot 50° c.) sin 50° d.) cos - id1505050504533326, heastonk9136

Ответ:

fernandar44

15.01.2022

$\cot 50 \textdegree$

Step-by-step explanation:

$\cos\theta=\frac{Adjacent}{Hypotenuse}\\ \\\sin\theta=\frac{Opposite}{hypotenuse}\\ \\\tan\theta=\frac{Opposite}{Adjacent}\\ \\\cot\theta=\frac{Adjacent}{Opposite}\\ \\\frac{\cos\theta}{\sin\theta}=\frac{\left(\frac{Adjacent}{Hypotenuse}\right)}{\left(\frac{Opposite}{Hypotenuse}\right)}=\frac{Adjacent}{Opposite}=\cot\theta\\ \\\Rightarrow \frac{\cos\theta}{\sin\theta}=\cot\theta\\ \\Substitute \ \theta=50\textdegree\\ \\\frac{\cos50\textdegree}{\sin50\textdegree}=\cot50\textdegree$

1.) a.) tan 50° b.) cot 50° c.) sin 50° d.) cos 50° e.) cot 50°

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Ответ:

alexandraschwartz21

22.10.2021

Mathematics

C. Free exercise clause to express religion

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1.)
a.) tan 50°
b.) cot 50°
c.) sin 50°
d.) cos 50°
e.) cot 50°

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